2Mg + O₂ → 2MgO Combination ✓ 2H₂O → 2H₂ + O₂ Decomposition ✓ Fe + CuSO₄ → FeSO₄ + Cu Displacement ✓ OIL RIG Oxidation Is Loss, Reduction Is Gain
Chapter 1  ·  Class X Science

The Language of Chemistry

Chemical Reactions and Equations

From Burning Magnesium to Rusting Iron — Decode Every Chemical Change

Chapter Snapshot

10Concepts
8Formulae / Reactions
8–10%Exam Weight
4–5Avg Q's
Easy-ModerateDifficulty

Why This Chapter Matters for Exams

CBSE BoardNTSEState Boards

Chemical Reactions and Equations opens Class X Science and contributes 8–10 marks in CBSE Boards. Balancing equations is a guaranteed 2-mark question. Types of reactions (combination, decomposition, displacement, double displacement, oxidation-reduction) are tested as both MCQs and short answers. NTSE includes chemical change identification and balancing.

Key Concept Highlights

Chemical Equation Writing
Balancing Chemical Equations
Types of Chemical Reactions
Combination Reactions
Decomposition Reactions (Thermal, Electrolytic, Photolytic)
Displacement Reactions
Double Displacement Reactions
Oxidation and Reduction
Redox Reactions
Effects of Oxidation in Daily Life (Corrosion, Rancidity)

Important Formulae & Reactions

$\text{Magnesium burning: } 2Mg + O_2 \rightarrow 2MgO$
$\text{Electrolysis of water: } 2H_2O \xrightarrow{\text{elec.}} 2H_2 + O_2$
$\text{Iron + CuSO}_4\text{: } Fe + CuSO_4 \rightarrow FeSO_4 + Cu$
$\text{NaOH + HCl: } NaOH + HCl \rightarrow NaCl + H_2O$
$\text{Barium + Na}_2\text{SO}_4\text{: } BaCl_2 + Na_2SO_4 \rightarrow BaSO_4 + 2NaCl$
$\text{Respiration: } C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O$
$\text{Photosynthesis: } 6CO_2 + 6H_2O \xrightarrow{\text{light}} C_6H_{12}O_6 + 6O_2$
$\text{Oxidation = loss of electrons / gain of oxygen}$

What You Will Learn

Navigate to Chapter Resources

🏆 Exam Strategy & Preparation Tips

Balancing equations is mechanical — practise 20+ equations until it becomes automatic. For "type of reaction" MCQs, remember: one product = combination; one reactant = decomposition; element displaces another = displacement. Redox: OIL RIG (Oxidation Is Loss, Reduction Is Gain). CBSE always asks one balancing + one type identification question.

Chapter 1 · CBSE · Class X
⚗️
Chemical Reaction
Chemical Reactions Equations Oxidation Reduction Corrosion Rancidity CBSE Class X NCERT
📘 Definition

Chemical Reaction

🔎 Key Fact

Observable Indicators of a Chemical Reaction

🎨 SVG Diagram
A B AB Reactants Product
💡 Concept

Conceptual Understanding

✏️ Example

Example 1: Burning of Magnesium

Reaction: \[ 2Mg + O_2 \rightarrow 2MgO \]

Observation: Bright white flame and white ash formation.

Example 2: Reaction of Zinc with Acid

Reaction: \[ Zn + 2HCl \rightarrow ZnCl_2 + H_2 \uparrow \]

Observation: Gas evolution (hydrogen).

🗺️ Roadmap

How to Identify a Chemical Reaction (Exam Roadmap)

  • Check if new substance is formed
  • Look for energy change (heat/light)
  • Observe physical indicators (gas, precipitate, colour)
  • Confirm irreversibility (most reactions)
🔢 Formula

Fundamental Law

🌟 Importance
⚠️ Warning

Common Mistakes Students Make

📋 Case Study

A student observes that when a solution of lead nitrate is mixed with potassium iodide, a yellow precipitate forms.

Question: Identify whether it is a chemical reaction. Justify.

Solution:

Reaction: \[ Pb(NO_3)_2 + 2KI \rightarrow PbI_2 \downarrow + 2KNO_3 \]

Since a new substance (yellow precipitate of PbI₂) is formed, it is a chemical reaction.

⚗️
Chemical Equations
📘 Definition

Definition

🔎 Key Fact

Components of a Chemical Equation

🗒️ Svg Diagram
2H₂ + O₂ Heat / Catalyst 2H₂O Reactants Products
✏️ Example

\[ 2H_2 + O_2 \rightarrow 2H_2O \]

🗒️ Result

Interpretation

Two molecules of hydrogen react with one molecule of oxygen to form two molecules of water.
📌 Note

Types of Chemical Equations

💡 Concept
🔢 Formula
\[ \text{Number of atoms of each element in reactants} = \text{Number of atoms in products} \]
🗒️ Raodmap

Exam Roadmap (How to Approach Questions)

  • Identify reactants and products clearly
  • Check if equation is balanced
  • Add coefficients, not subscripts
  • Include physical states when required
  • Mention reaction conditions if given
✏️ Example
Write and balance the equation for formation of water.
Hydrogen reacts with oxygen to form water.
  1. Write skeletal equation
  2. \[H_2 + O_2 \rightarrow H_2O\]
  3. Balance atoms
  4. \[2H_2 + O_2 \rightarrow 2H_2O\]
⚠️ Warning

Common Mistakes

📋 Case Study

A student writes the equation: \[ H_2 + O_2 \rightarrow H_2O \]

Question: Is this equation correct? Justify.

Answer:

No, the equation is not balanced. Oxygen atoms are not equal on both sides. Correct balanced equation: \[ 2H_2 + O_2 \rightarrow 2H_2O \]

🌟 Importance
⚗️
Writing a Chemical Equation
📘 Definition

Definition

💡 Concept

Concept Flow (Step-wise Conversion)

✏️ Example
When magnesium burns in oxygen, it forms magnesium oxide.
  1. Word Equation
  2. \[ \underset{\text{Reactants}}{\text{Magnesium} + \text{Oxygen}} \rightarrow \underset{\text{Product}}{\text{Magnesium oxide}} \]
  3. Skeletal Chemical Equation
  4. \[Mg + O_2 \rightarrow MgO\]
🎨 SVG Diagram
Magnesium + Oxygen Magnesium Oxide Mg + O₂ → MgO
📌 Note

Key Understanding

🔢 Formula

Important Rule

\[ \text{Always write correct chemical formulae before balancing} \]
⚡ Exam Tip
⚠️ Warning

Common Mistakes

📋 Case Study

A student writes the reaction of magnesium with oxygen as: \[ Mg + O \rightarrow MgO \]

Question: Identify the error and correct it.

Solution:

Oxygen exists as a diatomic molecule (O₂), not O. Correct skeletal equation: \[ Mg + O_2 \rightarrow MgO \]

🌟 Importance
⚗️
Balanced Equation
📘 Definition

Definition

✏️ Example
Word Equation: \[ \text{Zinc} + \text{Sulphuric acid} \rightarrow \text{Zinc sulphate} + \text{Hydrogen} \] Chemical Equation: \[ Zn + H_2SO_4 \rightarrow ZnSO_4 + H_2 \]

Balancing an Equation

  1. Write correct formulae: \[ Fe + H_2O \rightarrow Fe_3O_4 + H_2 \]
  2. List number of atoms for each element:
  3. Element Reactants (LHS) Products (RHS)
    Fe 1 3
    H 2 2
    O 1 4
  4. Begin with the most complex molecule:
  5. Choose \(Fe_3O_4\)
  6. Iron (Fe) Reactants Products
    Initial 1 (Fe) 3(Fe) in (Fe₃O₄)
    Balanced \(1 \times 3 = 3\) 3
  7. Updated equation: \[ 3Fe + H_2O \rightarrow Fe_3O_4 + H_2 \]
  8. Balance oxygen:
  9. Oxygen (O) Reactants Products
    Initial 1(O) in (H₂O) 4(O) in (Fe₃O₄)
    Balanced \(1 \times 4 = 4\) 4
  10. Updated equation: \[ 3Fe + 4H_2O \rightarrow Fe_3O_4 + H_2 \]
  11. Balance hydrogen
  12. Hydrogen (H) Reactants Products
    Initial 8(H) in (4H₂O) 2 (H) in (H₂)
    Balanced 8 \(2 \times 4 = 8\)
  13. Updated equation: \[ 3Fe + 4H_2O \rightarrow Fe_3O_4 + 4H_2 \]
  14. Verification: All atoms are equal on both sides.
  15. Final balanced equation (smallest ratio): \[ 3Fe + 4H_2O \rightarrow Fe_3O_4 + 4H_2 \]
  16. Writing physical states: \[ 3Fe(s) + 4H_2O(g) \rightarrow Fe_3O_4(s) + 4H_2(g) \]
3Fe + 4H₂O Fe₃O₄ + 4H₂
Examples (Fully Retained & Explained)
  1. \[CO(g) + H_2(g) \rightarrow CH_3OH(l)\]
  2. Elemet In Reactant (LHS) In Product (RHS)
    Carbon 1 (in \(CO\)) 1 (in \(CH_3OH\))
    Oxygen 1 (in \(CO\)) 1 (in \(CH_3OH\))
    Hydrogen 2 in \(H_2\)
    to balance: \(2\times 2\)
    4 (in \(CH_3OH\))
  3. Balanced: \[ CO + 2H_2 \rightarrow CH_3OH \]
<strong>\(HNO_3 +Ca(OH)_2 → Ca(NO_3)_2 + H_2O\)
Element In Reactant (LHS) In Product (RHS)
Calcium 1 (in \(Ca(OH)_2\)) 1 (in \(Ca(NO_3)_2\))
Nitrogen 1 (in \(HNO_3\))
To balance: \(1 \times 2\)
2 (in \(Ca(NO_3)_2\))
Partially Balanced Equation:
\[2HNO_3 + Ca(OH)_2 \rightarrow Ca(NO_3)_2 + H_2O\]
Oxygen 8 (6 in \(2HNO_3\) and 2 in \(Ca(OH)_2\)) 7 (6 in \(Ca(NO_3)_2\) and 1 in \(H_2O\))
To balance O: \(2 \times H_2O\)
Balanced Equation:
\[2HNO_3 + Ca(OH)_2 \rightarrow Ca(NO_3)_2 + 2H_2O\]
Hydrogen 4 (2 in \(2HNO_3\)) 4 (4 in \(2H_2O\))
Balanced Equation is:\[2HNO_3 + Ca(OH)_2 \rightarrow Ca(NO_3)_2 + 2H_2O\]
<strong>\(NaCl + AgNO_3 → AgCl + NaNO_3\)
Element In Reactant (LHS) In Product (RHS)
Sodium 1 (in \(NaCl\)) 1 (in \(NaNO_3\))
Silver 1 (in \(AgNO_3\)) 1 (in \(AgCl\))
Nitrogen 1 (in \(AgNO_3\)) 1 (1 in \(NaNO_3\))
Oxygen 3 (in \(AgNO_3\)) 3 (in \(NaNO_3\))
Equation is already in balanced state: \[NaCl + AgNO_3 → AgCl + NaNO_3\]
\[BaCl_2 +H_2SO_4 \rightarrow BaSO_4 +HCl\]
Element In Reactant (LHS) In Product (RHS)
Barium 1 (in \(BaCl_2\)) 1 in (\(in BaSO_4\))
Sulpher 1 (\(in H_2SO_4\)) 1 (in \(BaSO_4\))
Chlorine 2 (in \(BaCl_2\)) 1 (in \(HCl\))
to balance:
\(1\times 2 HCl\)
Partially Balanced Equation:\[BaCl_2 +H_2SO_4 \rightarrow BaSO_4 +2HCl\]
Oxygen 4 (in \(H_2SO_4\)) 4 (in \(BaSO_4\))
Hydrogen 2 (in \(H_2SO_4\)) 2 (in \(2HCl\))
Balanced Equation:\[BaCl_2 +H_2SO_4 \rightarrow BaSO_4 +2HCl\]
⚡ Exam Tip
⚠️ Warning

Common Mistakes

📋 Case Study

Balance: \[ Fe + H_2O \rightarrow Fe_3O_4 + H_2 \]

Answer:

\[ 3Fe + 4H_2O \rightarrow Fe_3O_4 + 4H_2 \]

⚗️
Types of Chemical Reactions
📘 Definition

Definition

📘 Definition

Combination Reaction

Definition: Two or more reactants combine to form a single product.

General form

\[ A + B \rightarrow AB \]
1
Example
\[CaO + H_2O \rightarrow Ca(OH)_2\]
Concept: Simpler substances combine to form a more complex compound.
📌
Note

Exam Tip: Usually exothermic (heat released).

📘 Definition

Decomposition Reaction

Definition: A single compound breaks into two or more simpler substances.

General Form

\[ AB \rightarrow A + B \]
2
Example
\[CaCO_3 \xrightarrow{\Delta} CaO + CO_2\]

Types

  • Thermal decomposition (heat)
  • Electrolytic decomposition (electric current)
  • Photolytic decomposition (light)
📌
Note

Exam Tip: Always requires energy (endothermic).

📘 Definition

Displacement Reaction

A more reactive element displaces a less reactive element from its compound.

General Form

\[ A + BC \rightarrow AC + B \]
3
Example
\[Zn + CuSO_4 \rightarrow ZnSO_4 + Cu\]
Based on reactivity series.
📌
Note

Exam Tip: Occurs only if the free element is more reactive.

📘 Definition

Double Displacement Reaction

Two compounds exchange ions to form new compounds.

Gemeral Form

\[ AB + CD \rightarrow AD + CB \]
4
Example
\[Na_2SO_4 + BaCl_2 \rightarrow BaSO_4 \downarrow + 2NaCl\]
Often results in precipitate formation.
📌
Note

Exam Tip: Look for insoluble product (precipitate).

📘 Definition

Oxidation and Reduction (Redox Reaction)

A reaction involving transfer of electrons between substances.
  • Oxidation: Loss of electrons / gain of oxygen / loss of hydrogen
  • Reduction: Gain of electrons / loss of oxygen / gain of hydrogen
5
Example
\[CuO + H_2 \rightarrow Cu + H_2O\]
📌
Note Here, CuO is reduced (loses oxygen) and H₂ is oxidized (gains oxygen).
📝 Summary

Quick Comparison Table

⚠️ Warning

Common Mistake

📋 Case Study

Identify the type of reaction: \[ Fe + CuSO_4 \rightarrow FeSO_4 + Cu \]

Answer: Displacement reaction because iron displaces copper.

⚗️
Combination Reaction
📘 Definition

Combination Reaction

✏️ Example

Calcium oxide reacts vigorously with water to produce slaked lime (calcium hydroxide), releasing a large amount of heat.

\[ \underset{\text{Quick Lime}}{CaO(s)} + H_2O(l) \rightarrow \underset{\text{Slaked Lime}}{Ca(OH)_2(aq)} + \text{Heat} \]

In this reaction, calcium oxide and water combine to form a single product, calcium hydroxide. Since two reactants form one product, it is a combination reaction.

🎨 SVG Diagram
CaO H₂O Ca(OH)₂ + Heat
💡 Concept
✏️ Example

More Examples

1
Example
Burning of coal: \[ C(s) + O_2(g) \rightarrow CO_2(g) \]

2
Example
Formation of water: \[ 2H_2(g) + O_2(g) \rightarrow 2H_2O(l) \]

3
Example
Formation of ammonia (industrial example): \[ N_2(g) + 3H_2(g) \rightarrow 2NH_3(g) \]
📝 Summary

How to Identify Quickly in Exams

⚡ Exam Tip
⚠️ Warning

Common Mistakes

📋 Case Study

Identify the type of reaction: \[ 2Mg + O_2 \rightarrow 2MgO \]

Answer: Combination reaction because two reactants combine to form a single product.

⚗️
Exothermic Reaction
📘 Definition

definition

🎨 SVG Diagram
Reaction Progress Energy e x1="95" y1="105" x2="150" y2="105" stroke="#4fc3f7" stroke-width="2"/> Reactants e x1="445" y1="150" x2="515" y2="150" stroke="#81c784" stroke-width="2"/> Products e x1="250" y1="35" x2="250" y2="105" stroke="#ffb74d" stroke-width="1.5" stroke-dasharray="5,4"/> Activation Energy e x1="525" y1="105" x2="525" y2="150" stroke="#e57373" stroke-width="1.5" stroke-dasharray="4,3"/> ΔH < 0 Energy Released
✏️ Example

Examples

1
Example
Combustion: A substance reacts rapidly with oxygen to release heat and light. \[C + O_2 \rightarrow CO_2 + \text{Heat}\]

2
Example
Neutralization: An acid reacts with a base to produce salt and water. \[NaOH + HCl \rightarrow NaCl + H_2O + \text{Heat}\]

3
Example
Nuclear Fission: A heavy nucleus splits into smaller nuclei releasing enormous energy.

4
Example
Respiration: Energy is released when glucose reacts with oxygen in cells.

\[ C_6H_{12}O_6(aq) + 6O_2(aq) \rightarrow 6CO_2(aq) + 6H_2O(l) + \text{Energy} \]


5
Example
Calcium oxide and water: \[ CaO + H_2O \rightarrow Ca(OH)_2 + \text{Heat} \]
💡 Concept
⚗️
Endothermic Reaction
📘 Definition

Definition

🎨 SVG Diagram
Reaction Progress Energy Reactants Products Activation Energy ΔH > 0
✏️ Example

Examples of Endothermic Reactions

1
Example
Melting of ice (solid → liquid)

2
Example
Evaporation of water

3
Example
Photosynthesis: \[ 6CO_2 + 6H_2O \xrightarrow{\text{Sunlight}} C_6H_{12}O_6 + 6O_2 \]

4
Example
Dissolving ammonium nitrate in water (used in cold packs)
📝 Summary

Exothermic vs Endothermic

⚡ Exam Tip
⚠️ Warning

Common Mistakes

📋 Case Study

Ice melts when kept outside. Identify the type of reaction.

Answer: Endothermic because heat is absorbed from surroundings.

⚗️
Decomposition Reaction
📘 Definition

Definition

💡 Concept
🎨 SVG Diagram
AB A B
🔢 Formula

Important Industrial Reaction

1
Example

Decomposition of calcium carbonate:

\[ CaCO_3 \xrightarrow{\Delta} CaO + CO_2 \]

This reaction is used in the manufacture of cement and quick lime.


2
Example

Thermal decomposition of lead nitrate:

\[ 2Pb(NO_3)_2 \xrightarrow{\Delta} 2PbO + 4NO_2 + O_2 \]


3
Example

Photochemical decomposition:

\[ 2AgCl \xrightarrow{\text{Sunlight}} 2Ag + Cl_2 \]

\[ 2AgBr \xrightarrow{\text{Sunlight}} 2Ag + Br_2 \]

📌 Note

Types of Decomposition Reactions

🔎 Key Fact

How to Identify Quickly

⚡ Exam Tip
⚠️ Warning

Common Mistakes

📋 Case Study

Identify the type of reaction: \[ CaCO_3 \xrightarrow{\Delta} CaO + CO_2 \]

Answer: Decomposition reaction (thermal).

⚗️
Displacement Reaction
📘 Definition

Definition

💡 Concept
🔤 Mnemonic

Mnemonic (Rhyme to Learn)

🧠 Remember
🎨 SVG Diagram
Zn CuSO₄ ZnSO₄ Cu
✏️ Example

Examples of Displacement Reactions

1
Example
\[ Fe + CuSO_4 \rightarrow FeSO_4 + Cu \]
Iron is more reactive than copper, so it displaces copper.


2
Example
\[ Zn + CuSO_4 \rightarrow ZnSO_4 + Cu \]
Zinc is more reactive than copper.


3
Example
\[ Pb + CuCl_2 \rightarrow PbCl_2 + Cu \]
Lead displaces copper.


4
Important Non-Example
\[ Cu + FeSO_4 \rightarrow \text{No Reaction} \]

Copper is less reactive than iron, so it cannot displace iron.

📝 Summary

How to Identify in Exams

⚡ Exam Tip
⚠️ Warning

Common Mistakes

📋 Case Study

Will the following reaction occur? \[ Cu + ZnSO_4 \rightarrow ? \]

Answer: No reaction, because copper is less reactive than zinc.

⚗️
Double Displacement Reaction
📘 Definition

Definition

💡 Concept

How it Happens (Ionic Perspective)

📖 Theory

Condition for Reaction to Occur

✏️ Example

Examples (Precipitation Reaction)

⚗️ Molecular equation
Na2SO4(aq) + BaCl2(aq) BaSO4(s) ↓ + 2NaCl(aq)
⚗️ Ionic representation
2Na+ + SO42- + Ba2+ + 2Cl- BaSO4 ↓ + 2Na+ + 2Cl-
⚗️ Net ionic equation
Ba2+ + SO42- BaSO4
📌
Note

A white precipitate of BaSO₄ is formed. Sodium chloride remains dissolved in the solution.

🎨 SVG Diagram
Na₂SO₄ BaCl₂ BaSO₄↓ NaCl
📌 Note

Precipitation Reaction

✏️ Example

MOre Examples

⚗️ Double displacement
AgNO3 + NaCl AgCl ↓ + NaNO3
⚗️ Double displacement (neutralization reaction)
HCl + NaOH NaCl + H2O
📝 Summary

How to Identify in Exams

⚡ Exam Tip
⚠️ Warning

Common Mistakes

📋 Case Study

Identify the type of reaction: \[ AgNO_3 + NaCl \rightarrow AgCl\downarrow + NaNO_3 \]

Answer: Double displacement (precipitation reaction).

⚗️
Redox Reaction (Oxidation–Reduction Reaction)
📘 Definition

Definition

💡 Concept

What Happens in a Redox Reaction?

🔤 Mnemonic

OIL RIG

Memory Trick
🎨 SVG Diagram
Loss e⁻ Oxidation Gain e⁻ Reduction
✏️ Example

Examples (Detailed Explanation)

1
Example

Copper Oxide + Hydrogen

\[ CuO + H_2 \rightarrow Cu + H_2O \]

• CuO loses oxygen → Reduction
• H₂ gains oxygen → Oxidation

Half reactions: \[ Cu^{2+} + 2e^- \rightarrow Cu \quad (\text{Reduction}) \] \[ H_2 \rightarrow 2H^+ + 2e^- \quad (\text{Oxidation}) \]

2
Example

Zinc Oxide + Carbon

\[ ZnO + C \rightarrow Zn + CO \]

• ZnO loses oxygen → Reduction
• Carbon gains oxygen → Oxidation

\[ Zn^{2+} + 2e^- \rightarrow Zn \quad (\text{Reduction}) \] \[ C \rightarrow C^{2+} + 2e^- \quad (\text{Oxidation}) \]

3
Example

\[ MnO_2 + 4HCl \rightarrow MnCl_2 + H_2O + Cl_2 \]

• HCl loses hydrogen → Oxidation
• MnO₂ loses oxygen → Reduction

4
Example

\[ 2Mg + O_2 \rightarrow 2MgO \]

• Mg loses electrons → Oxidation
• O₂ gains electrons → Reduction

📌 Note

Key Insight

📝 Summary
Identification
⚡ Exam Tip
⚠️ Warning
Common Mistakes
📋 Case Study

Identify oxidation and reduction: \[ Fe_2O_3 + 3CO \rightarrow 2Fe + 3CO_2 \]

Answer:

• Fe₂O₃ is reduced (loses oxygen)
• CO is oxidized (gains oxygen)

⚗️
Oxidising Agent
📘 Definition

definition

💡 Concept
How Does an Oxidising Agent Work?
📌 Note
Key Insight
🎨 SVG Diagram
Loses e⁻ Gains e⁻ Oxidising Agent
✏️ Example
Examples of Oxidising Agents
  • Oxygen \((O_2)\)
  • Hydrogen peroxide \((H_2O_2)\)
  • Halogens: Chlorine \((Cl_2)\), Fluorine \((F_2)\), Bromine \((Br_2)\), Iodine \((I_2)\)
Why Halogens are Strong Oxidising Agents
  • High electronegativity → strong tendency to attract electrons
  • Easily gain electrons to form negative ions
  • Strong oxidising power increases up the group
  • Fluorine is the strongest oxidising agent due to highest electronegativity
⚗️ Redox / Electron Transfer
CuO + H2 Cu + H2O
📌
Note

• CuO acts as oxidising agent (it provides oxygen and gets reduced)
• H₂ acts as reducing agent

📌 Note
Identification
⚡ Exam Tip
⚠️ Warning
Common Mistakes
📋 Case Study

Identify oxidising agent: \[ Fe_2O_3 + 3CO \rightarrow 2Fe + 3CO_2 \]

Answer:

Fe₂O₃ is the oxidising agent because it loses oxygen and gets reduced.

⚗️
Reducing Agent
📘 Definition

definition

💡 Concept
How Does a Reducing Agent Work?
📌 Note
Key Insight
🎨 SVG Diagram
Donates e⁻ Gains e⁻ Reducing Agent
✏️ Example

\[ CuO + H_2 \rightarrow Cu + H_2O \]

• H₂ donates electrons → Reducing agent
• CuO gains electrons → reduced

  • Alkali and alkaline earth metals (Na, K, Ca, Mg)
  • Hydrogen \((H_2)\)
  • Carbon \((C)\) and carbon monoxide \((CO)\)
  • Formic acid and sulfite compounds
📌 Note
Identification
⚡ Exam Tip
⚠️ Warning

Common Mistakes

📋 Case Study

Identify reducing agent: \[ Fe_2O_3 + 3CO \rightarrow 2Fe + 3CO_2 \]

Answer:

CO is the reducing agent because it donates electrons and gets oxidized to CO₂.

📝 Summary
Oxidising vs Reducing Agent (Quick Comparison)
⚗️
Corrosion
📘 Definition

Definition

🌟 Importance
📌 Note
How Does Corrosion Occur?
✏️ Example
Rusting of Iron

Rusting is the most common example of corrosion. It occurs when iron reacts with oxygen and water.

\[ 4Fe + 3O_2 + xH_2O \rightarrow 2Fe_2O_3 \cdot xH_2O \]

The reddish-brown substance formed is called rust (hydrated iron(III) oxide).

🎨 SVG Diagram
Iron (Fe) Rust (Fe₂O₃·xH₂O) O₂ + H₂O
📌 Note
Conditions Necessary for Rusting
📌 Note
Prevention of Corrosion
✏️ Example
Everyday Applications
  • Stainless steel utensils resist rusting
  • Galvanized pipes used in plumbing
  • Painted gates and railings last longer
  • Oiled bicycle chains prevent rust
💡 Concept
Concept Insight
⚡ Exam Tip
⚠️ Warning
Common Mistakes
📋 Case Study

Why does rusting not occur in dry air?

Answer:

Rusting requires moisture (water). In dry air, water is absent, so rusting does not occur.

⚗️
Rancidity
📘 Definition

Definition

💡 Concept
📌 Note
How Does Rancidity Occur?
🎨 SVG Diagram
Fresh Oil Rancid O₂ + Time + Heat
✏️ Example
  • Potato chips or snacks left open develop bad smell
  • Butter or ghee becomes foul-smelling when exposed to air
  • Cooking oil stored for long becomes unpleasant
📌 Note
Prevention of Rancidity
📌 Note
Concept Insight
⚡ Exam Tip
⚠️ Warning
Common Mistakes
🗒️ Case Atudy

Why are chips packets filled with nitrogen gas instead of air?

Answer:

Nitrogen is an inert gas and prevents oxidation of oils, thereby preventing rancidity.

NCERT Science Class X · Chapter 1
Chemical Reactions & Equations

A complete self-contained learning engine — concept cards, AI-powered solver, step-by-step solutions, interactive modules, and everything you need to master Chapter 1.

8Core Concepts
28Key Equations
15Solved Questions
3Interactive Modules
30+AI Topics

Core Concepts

Eight fundamental ideas that form the backbone of Chapter 1 — each with key equations and real-world context.

⚗️ Foundation

Chemical Reactions

A process in which substances (reactants) transform into new substances (products) with different properties. Evidenced by observable changes.

Observable Signs:

  • Change in colour or state
  • Evolution of gas (↑) or formation of precipitate (↓)
  • Change in temperature
  • Change in smell
Reactants → Products
(e.g. Mg + O₂ → MgO)
⚖️ Skill

Balancing Equations

Based on the Law of Conservation of Mass: atoms are neither created nor destroyed in a reaction. Both sides must have equal atoms of each element.

Hit-and-Trial Method: Adjust coefficients (NOT subscripts) until atoms balance on both sides. Always check each element.
Unbalanced: H₂ + O₂ → H₂O
Balanced: 2H₂ + O₂ → 2H₂O ✓
🔗 Reaction Type

Combination Reactions

Two or more substances combine to form a single new substance. Often exothermic (release heat). Both reactants can be elements, compounds, or mixtures.

Formula: A + B → AB

CaO + H₂O → Ca(OH)₂ + Heat
2Mg + O₂ → 2MgO
C + O₂ → CO₂
💥 Reaction Type

Decomposition Reactions

A single compound breaks down into two or more simpler substances. Requires energy (heat, electricity, or light).

  • Thermal: Heat (Δ) as energy
  • Electrolytic: Electric current
  • Photolytic: Light (hν)
AB → A + B
CaCO₃ →Δ CaO + CO₂↑
↔️ Reaction Type

Displacement Reactions

A more reactive element displaces a less reactive element from its salt solution. Governed by the Activity Series (Reactivity Series).

Formula: A + BC → AC + B (A more reactive than B)

Fe + CuSO₄ → FeSO₄ + Cu
Zn + H₂SO₄ → ZnSO₄ + H₂↑
🔄 Reaction Type

Double Displacement

Ions from two compounds exchange partners to form two new compounds. Usually involves formation of a precipitate (↓), gas (↑), or water. Also called metathesis.

Formula: AB + CD → AD + CB

Na₂SO₄ + BaCl₂ → BaSO₄↓ + 2NaCl
AgNO₃ + NaCl → AgCl↓ + NaNO₃
Redox

Oxidation & Reduction

Always occur simultaneously (Redox reactions). Use OIL RIG as your memory aid.

Oxidation Loss of e⁻ or H₂
Gain of O₂
Oxidation State ↑
Reduction Gain of e⁻ or H₂
Loss of O₂
Oxidation State ↓
CuO + H₂ → Cu + H₂O
Cu: +2→0 (reduced) | H: 0→+1 (oxidised)
🦠 Everyday Chemistry

Corrosion & Rancidity

Two important effects of oxidation in daily life:

Corrosion: Metals oxidised by air/moisture. Iron rusts (Fe₂O₃·xH₂O), silver tarnishes (Ag₂S), copper turns green (Cu(OH)₂·CuCO₃).

Rancidity: Fats/oils oxidised, developing bad taste/smell. Prevented by antioxidants, airtight packing, refrigeration, N₂ flushing.

4Fe + 3O₂ + xH₂O → 2Fe₂O₃·xH₂O
(Rusting of iron)

📌 State Symbols & Conventions

(s) Solid state
(l) Liquid state
(g) Gaseous state
(aq) Aqueous solution
Gas evolved
Precipitate formed
Δ Heat applied
Reaction proceeds

Key Equations & Formulae

All major balanced chemical equations from Chapter 1, organised by reaction type with names and notes.

🔗 Combination Reactions
CaO(s) + H₂O(l) → Ca(OH)₂(aq)
Calcium oxide + Water → Calcium hydroxide (Slaked lime). Highly exothermic.
Exothermic
2Mg(s) + O₂(g) →Δ 2MgO(s)
Magnesium burns in oxygen — dazzling white flame, forms magnesium oxide (basic)
Combustion
C(s) + O₂(g) → CO₂(g)
Carbon burns in excess oxygen → Carbon dioxide (complete combustion)
Combustion
N₂(g) + 3H₂(g) ⇌ 2NH₃(g)
Haber Process — Nitrogen + Hydrogen → Ammonia (reversible at high T, P)
Reversible
💥 Decomposition Reactions
CaCO₃(s) →Δ CaO(s) + CO₂(g)↑
Limestone heated → Quicklime + CO₂. Industrial basis of cement manufacture.
Thermal
2FeSO₄(s) →Δ Fe₂O₃(s) + SO₂(g)↑ + SO₃(g)↑
Ferrous sulphate heated → Ferric oxide (brown) + pungent gases SO₂ & SO₃
Thermal
2H₂O(l) →elec. 2H₂(g)↑ + O₂(g)↑
Electrolysis of water. H₂ at cathode (2× vol.), O₂ at anode. Ratio 2:1.
Electrolytic
2AgCl(s) → 2Ag(s) + Cl₂(g)↑
Silver chloride decomposes in sunlight → grey metallic silver. Basis of photography.
Photolytic
2AgBr(s) → 2Ag(s) + Br₂(g)↑
Silver bromide → Silver + Bromine. Used in black & white photography.
Photolytic
2Pb(NO₃)₂(s) →Δ 2PbO(s) + 4NO₂(g)↑ + O₂(g)↑
Lead nitrate heated → Lead oxide (yellow) + brown NO₂ + O₂ gases
Thermal
↔️ Displacement Reactions
Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s)
Iron nail in copper sulphate (blue→green). Copper deposited. Fe more reactive than Cu.
Single
Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s)
Zinc displaces copper — blue solution decolourises, copper deposits. Zn > Cu.
Single
Zn(s) + H₂SO₄(aq) → ZnSO₄(aq) + H₂(g)↑
Zinc reacts with dilute sulphuric acid — hydrogen gas evolves (brisk effervescence).
Single
Fe₂O₃(s) + 2Al(s) → Al₂O₃(s) + 2Fe(l)
Thermite reaction — Al displaces Fe. Temp ~2500°C. Liquid iron used for rail welding.
Thermite
🔄 Double Displacement Reactions
Na₂SO₄(aq) + BaCl₂(aq) → BaSO₄(s)↓ + 2NaCl(aq)
White precipitate of barium sulphate (BaSO₄) — insoluble in dilute acids. Standard test.
Precipitate
Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s)↓ + 2KNO₃(aq)
Lead iodide — bright yellow precipitate. Classic demonstration of double displacement.
Precipitate
AgNO₃(aq) + NaCl(aq) → AgCl(s)↓ + NaNO₃(aq)
White AgCl precipitate — curdy white, turns grey/purple in light. Test for Cl⁻ ions.
Precipitate
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
Neutralisation reaction — acid + base → salt + water. Exothermic double displacement.
Neutralisation
⚡ Oxidation–Reduction (Redox) Reactions
CuO(s) + H₂(g) →Δ Cu(s) + H₂O(l)
CuO reduced to Cu (gains H₂); H₂ oxidised to H₂O (gains O). Black→brown colour change.
Redox
MnO₂ + 4HCl → MnCl₂ + Cl₂↑ + 2H₂O
MnO₂ oxidises HCl to Cl₂ (yellowish-green gas). Mn: +4→+2 (reduced), Cl: −1→0 (oxidised).
Redox
CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)
Methane combustion — complete oxidation. Carbon: −4→+4 (oxidised); O₂ reduced.
Combustion
4Fe(s) + 3O₂(g) + xH₂O → 2Fe₂O₃·xH₂O
Rusting of iron — slow oxidation in presence of water and oxygen. Fe: 0→+3.
Corrosion

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Concept-Building Questions

Original, exam-oriented questions with full step-by-step solutions — organised by concept, each question building deeper understanding.

1
Balancing Easy
Balance the equation step by step using the hit-and-trial method: Al + O₂ → Al₂O₃. State the law that makes balancing necessary.
⚖️
The Law

Law of Conservation of Mass: In any chemical reaction, the total mass of reactants equals the total mass of products. Atoms cannot be created or destroyed — only rearranged. This makes balancing compulsory.

1️⃣
Step 1 — Write the skeleton equation

Al + O₂ → Al₂O₃
Count atoms: Left: Al=1, O=2 | Right: Al=2, O=3 — Not balanced.

2️⃣
Step 2 — Balance Al

Right side has 2 Al → put coefficient 2 on left Al:
2Al + O₂ → Al₂O₃
Al: 2=2 ✓ | O: 2 ≠ 3 ✗

3️⃣
Step 3 — Balance O (LCM method)

Left O₂ gives O in multiples of 2; right Al₂O₃ gives O in multiples of 3.
LCM(2,3) = 6. Need 3O₂ on left and 2Al₂O₃ on right.
This also means Al on left must be 4Al:

4Al + 3O₂ → 2Al₂O₃
Verification

Al: Left = 4 | Right = 2×2 = 4 ✓
O: Left = 3×2 = 6 | Right = 2×3 = 6 ✓

Final Answer

4Al + 3O₂ → 2Al₂O₃

2
Balancing Medium
Priya observes that a freshly cut apple turns brown after 20 minutes. Is this a physical or chemical change? Give FOUR lines of evidence and write a simplified equation for the process.
🍎
Classification

This is a chemical change — the browning is caused by the enzymatic oxidation of phenolic compounds (like catechol) in the apple when exposed to atmospheric oxygen (O₂), forming melanin pigments.

📋
Four Pieces of Evidence
  • New substance formed: Melanin (brown pigment) is a completely different compound from the original phenols.
  • Irreversible change: The brown apple cannot be turned back to its original white state.
  • Change in properties: Taste becomes slightly bitter; texture softens at the cut surface.
  • Absorption of O₂: The process requires oxygen (removing O₂ by vacuum or coating with lemon juice slows it).
⚗️
Simplified Equation
Catechol (C₆H₄(OH)₂) + O₂ →Enzyme Melanin (brown) + H₂O
Key Point

Chemical changes: involve new substance formation, energy exchange, and are generally irreversible.

3
Combination Easy
Quick lime (CaO) is added to an agricultural field to treat acidic soil. Write the reaction with water, name the product, classify the reaction type, and explain why the reaction vessel becomes hot.
⚗️
Balanced Equation
CaO(s) + H₂O(l) → Ca(OH)₂(aq) + Heat
🏷️
Product Name

Calcium hydroxide — also called Slaked lime. It is an alkali used to neutralise soil acidity.

📂
Classification

Combination Reaction (two substances → one product) AND Exothermic Reaction (releases heat energy to surroundings).

🔥
Why Does It Get Hot?

In an exothermic reaction, the chemical bonds formed in the product (Ca–OH bonds in Ca(OH)₂) release more energy than is required to break the reactant bonds. This excess energy is released as heat, raising the temperature of the surroundings.

4
Decomposition Medium
Ferrous sulphate crystals (FeSO₄·7H₂O) are heated in a test tube. Describe the step-by-step observations and write the decomposition equation. What type of decomposition is this?
1️⃣
Observation 1 — Loss of Water

The light green crystals gradually lose their water of crystallisation. The crystals first shrink and become a white/pale powder (anhydrous FeSO₄).

2️⃣
Observation 2 — Colour Change

On further heating, the white FeSO₄ powder turns reddish-brown as Fe₂O₃ (ferric oxide) is formed. This is a clear sign of a new substance being produced.

3️⃣
Observation 3 — Pungent Smell

A sharp, acrid smell is noticed — this is due to SO₂ and SO₃ gases being evolved. A damp litmus paper turns red (acidic nature confirmed).

⚗️
Equation
2FeSO₄(s) →Δ Fe₂O₃(s) + SO₂(g)↑ + SO₃(g)↑
Type

Thermal Decomposition — heat provides the activation energy needed to break down FeSO₄ into simpler compounds.

5
Decomposition Medium
Compare the energy source in three types of decomposition reactions with one example each. Also state one practical application of each type.
🔥
1. Thermal Decomposition

Energy Source: Heat (Δ)

CaCO₃ →Δ CaO + CO₂↑

Application: Industrial production of quicklime (CaO) used in cement manufacturing and for treating acidic soil.

2. Electrolytic Decomposition

Energy Source: Electric current

2H₂O(l) →Electricity 2H₂(g)↑ + O₂(g)↑

Application: Hydrogen fuel production; extraction of metals like aluminium and sodium from their molten salts (electrolytic refining).

💡
3. Photolytic Decomposition

Energy Source: Light (hν — photons)

2AgBr(s) → 2Ag(s) + Br₂(g)↑

Application: Black & white photography; photochromic lenses (darken in sunlight due to AgCl decomposition, become clear indoors).

6
Displacement Medium
Using the activity series (Zn > Fe > Cu), predict and write equations for: (a) Fe dipped in CuSO₄, (b) Cu dipped in ZnSO₄, (c) Zn dipped in FeSO₄. Describe the observation for each.
(a)
Fe in CuSO₄ — Reaction Occurs ✓

Iron is more reactive than copper, so Fe displaces Cu from its salt solution.

Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s)

Observation: Blue solution gradually turns light green (FeSO₄ is pale green). Reddish-brown copper metal deposits on the iron surface.

(b)
Cu in ZnSO₄ — No Reaction ✗

Copper is LESS reactive than zinc. A less reactive metal cannot displace a more reactive one from its solution.

Observation: No change in the colour of solution or appearance of copper strip. The solution remains colourless.

(c)
Zn in FeSO₄ — Reaction Occurs ✓

Zinc is more reactive than iron, so Zn displaces Fe from its salt solution.

Zn(s) + FeSO₄(aq) → ZnSO₄(aq) + Fe(s)

Observation: Pale green solution of FeSO₄ becomes colourless (ZnSO₄ solution). Grey iron deposits on the zinc strip.

7
Displacement Hard
The Thermite Reaction: Fe₂O₃ + Al → Al₂O₃ + Fe. (a) Balance this equation. (b) Why is Al able to displace Fe? (c) Why does this reaction produce liquid iron? (d) State one industrial application with explanation.
(a)
Balancing the Thermite Equation

Skeleton: Fe₂O₃ + Al → Al₂O₃ + Fe

Fe: Left=2, Right=1 → put 2Fe on right. Al: Left=1, Right=2 → put 2Al on left. O: Left=3, Right=3 ✓

Fe₂O₃(s) + 2Al(s) → Al₂O₃(s) + 2Fe(l)

Check: Fe 2=2 ✓ | Al 2=2 ✓ | O 3=3 ✓

(b)
Why Al Displaces Fe

Aluminium is higher in the activity series than iron. More reactive metals have a greater tendency to lose electrons and form oxides. Al therefore has a stronger drive to form Al₂O₃ than Fe does to remain as Fe₂O₃, so it displaces iron.

(c)
Why Liquid Iron?

The thermite reaction is highly exothermic — it releases enormous heat, reaching temperatures of approximately 2500°C. Since the melting point of iron is only 1538°C, the iron produced is immediately in the liquid (molten) state.

(d)
Industrial Application

Railway Track Welding (Thermite Welding): The liquid iron flows into the gap between two rail sections and solidifies, creating a seamless, strong weld. No external power source is needed — the reaction is self-sustaining once ignited.

8
Double Displacement Medium
When barium chloride solution is mixed with sodium sulphate solution, a white precipitate forms. Identify the precipitate, write the balanced molecular and ionic equations, and classify the reaction type fully.
⚗️
Molecular Equation
BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s)↓ + 2NaCl(aq)

Precipitate: Barium sulphate (BaSO₄) — white solid, insoluble in water and dilute acids.

🔬
Net Ionic Equation
Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)↓

The spectator ions Na⁺ and Cl⁻ are not shown as they don't participate in the reaction.

📂
Classification

Double Displacement Reaction — Ba²⁺ and Na⁺ exchange their anions (Cl⁻ and SO₄²⁻). Also classified as a Precipitation Reaction since an insoluble product (precipitate) forms.

9
Redox Medium
In the reaction: CuO + H₂ → Cu + H₂O. Using OIL RIG: (a) What is oxidised? (b) What is reduced? (c) Identify the oxidising agent and reducing agent. (d) State the colour change observed.
📝
OIL RIG Framework

OIL: Oxidation Is Loss of electrons
RIG: Reduction Is Gain of electrons

CuO(s) + H₂(g) →Δ Cu(s) + H₂O(l)
(a)
What is Oxidised?

Hydrogen (H₂) is oxidised.
H₂: oxidation state = 0 → in H₂O: +1. Increase in oxidation state = loss of electrons = Oxidation.

(b)
What is Reduced?

Copper (Cu in CuO) is reduced.
Cu in CuO: +2 → Cu metal: 0. Decrease in oxidation state = gain of electrons = Reduction.

(c)
Oxidising and Reducing Agents

Oxidising Agent: CuO — it oxidises H₂ (and gets reduced itself).
Reducing Agent: H₂ — it reduces CuO (and gets oxidised itself).

Rule: The substance that gets oxidised IS the reducing agent. The substance that gets reduced IS the oxidising agent.
(d)
Colour Change

Black copper(II) oxide (CuO) → reddish-brown metallic copper (Cu).
Colour change: Black → Reddish-brown

10
Redox Hard
In MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O: (a) Identify oxidation state changes for Mn and Cl. (b) What is oxidised and what is reduced? (c) Identify the oxidising and reducing agents. (d) What colour change is observed?
(a)
Oxidation State Changes

Mn: In MnO₂ → +4 | In MnCl₂ → +2 | Change: +4 → +2 (decrease by 2)

Cl: In HCl → −1 | In Cl₂ → 0 | Change: −1 → 0 (increase by 1)

(b)
Oxidised and Reduced

Cl (in HCl) is Oxidised: oxidation state increases from −1 to 0.

Mn (in MnO₂) is Reduced: oxidation state decreases from +4 to +2.

(c)
Oxidising and Reducing Agents

Oxidising Agent: MnO₂ — it accepts electrons from HCl (gets reduced from +4 to +2).

Reducing Agent: HCl — it donates electrons (Cl gets oxidised from −1 to 0).

(d)
Observation

Black MnO₂ dissolves; yellowish-green Cl₂ gas evolves with a characteristic pungent smell. The solution becomes pale pink/colourless (MnCl₂ is very pale pink).

11
Corrosion Medium
Iron railings near a swimming pool corrode much faster than those inside a dry gymnasium. Give THREE scientific reasons for this difference and suggest two effective prevention methods with chemical explanation.
🏊
Three Reasons for Faster Corrosion Near Pool
  • Higher humidity: Water vapour acts as a medium (electrolyte) for the electrochemical oxidation of Fe. Fe + O₂ + H₂O → rust is significantly accelerated.
  • Chlorine ions (Cl⁻): Pool water contains chlorine. Cl⁻ ions break down the passive oxide layer on iron, exposing fresh metal to further attack.
  • Temperature variations: Outdoor temperature fluctuations cause expansion/contraction, creating micro-cracks in any protective layer, exposing more iron surface.
🛡️
Two Prevention Methods

1. Galvanisation (Zinc Coating): A layer of zinc (Zn) is applied to iron. Zn is more reactive — it acts as a sacrificial anode, oxidising preferentially and protecting iron even if the coating is scratched: Zn → Zn²⁺ + 2e⁻ (instead of Fe).

2. Electroplating with Chromium/Nickel: An inert, hard metal coat prevents O₂ and H₂O from contacting iron at all. No contact = no electrochemical cell = no rust.

12
Rancidity Medium
A crisp manufacturer flushes packets with nitrogen gas instead of air. Explain the chemistry of rancidity and precisely how nitrogen prevents it. List THREE other methods of preventing rancidity.
🧪
Chemistry of Rancidity

Fats and oils contain unsaturated fatty acid chains (C=C double bonds). Atmospheric O₂ attacks these double bonds in a process called auto-oxidation:

Unsaturated fat + O₂ → Peroxides → Aldehydes/Ketones
(Stale/sour smell + altered taste)

This is an oxidation reaction producing hydroperoxides and then breakdown products that smell/taste rancid.

🫧
How Nitrogen Prevents Rancidity

Nitrogen (N₂) is a chemically inert gas — it does not react with fats or oils. By replacing air with N₂ in the packet, all oxygen is excluded. Without O₂, auto-oxidation cannot begin, and the fats remain fresh indefinitely (until the packet is opened).

📋
Three Other Prevention Methods
  • Antioxidants (BHA, BHT, Vit E): These molecules donate hydrogen atoms to free radicals, breaking the oxidation chain reaction before it damages fats.
  • Refrigeration: Low temperature slows the rate of oxidation reaction (reaction rate decreases with temperature).
  • Airtight packaging: Vacuum-sealed containers reduce O₂ availability, preventing contact between fat and oxygen.
13
Combination Hard
A student burns magnesium ribbon in air and finds the product is heavier than the original magnesium. Another student argues this violates conservation of mass. Resolve this apparent contradiction with chemical evidence.
💡
The Apparent Contradiction Explained

The second student's argument incorrectly assumes only the magnesium's mass should be considered. The Law of Conservation of Mass applies to the total mass of ALL reactants — not just one of them.

⚗️
Balanced Equation
2Mg(s) + O₂(g) → 2MgO(s)

Here, Mg combines with O₂ from the air. Mass of MgO = Mass of Mg + Mass of O₂ consumed.

🔢
Numerical Example

If 24g of Mg reacts with 16g of O₂ → 40g of MgO is formed.
Total Reactant mass = 24 + 16 = 40g
Total Product mass = 40g

The product is heavier than Mg alone because it incorporates the mass of oxygen from air.

Conclusion

Conservation of Mass holds perfectly. The extra mass in MgO comes from atmospheric O₂ that combined with Mg.

14
Decomposition Hard
In the electrolysis of water: (a) Write the balanced equation, (b) Name the gases at each electrode, (c) State the volume ratio, (d) Why is dilute H₂SO₄ or NaOH added? (e) How would you test each gas?
(a)
Balanced Equation
2H₂O(l) →Electricity 2H₂(g)↑ + O₂(g)↑
(b)
Gases at Each Electrode

Cathode (–ve): Hydrogen gas (H₂) — H⁺ ions gain electrons here (reduction).
Anode (+ve): Oxygen gas (O₂) — OH⁻ ions lose electrons here (oxidation).

(c)
Volume Ratio

H₂ : O₂ = 2 : 1
From the equation, 2 moles H₂ and 1 mole O₂ are produced. By Avogadro's law, equal moles of gases occupy equal volumes → ratio is 2:1.

(d)
Why Add Dilute H₂SO₄ or NaOH?

Pure water is a very poor conductor of electricity (very few ions). Adding dilute H₂SO₄ or NaOH provides ions (H⁺, SO₄²⁻ or Na⁺, OH⁻) that carry the current through the solution, making electrolysis possible.

(e)
Testing the Gases

Testing H₂: Bring a burning splint near the tube — H₂ burns with a blue flame and a characteristic "pop" sound.

Testing O₂: Bring a glowing splint near the tube — O₂ relights the glowing splint (supports combustion).

15
Redox / Corrosion Hard
Classify EACH of the following as combination, decomposition, displacement, double displacement, or redox (some may have multiple types). Give a brief justification for each: (a) 2Na + Cl₂ → 2NaCl (b) 2KClO₃ → 2KCl + 3O₂ (c) Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag (d) NaOH + HCl → NaCl + H₂O
(a)
2Na + Cl₂ → 2NaCl

Combination + Redox.
Two substances → one product (Combination). Also: Na: 0 → +1 (oxidised); Cl: 0 → −1 (reduced) — Redox occurs simultaneously.

(b)
2KClO₃ →Δ, MnO₂ 2KCl + 3O₂

Thermal Decomposition + Redox.
One compound → simpler products (Decomposition). Cl: +5 → −1 (reduced); O: −2 → 0 in O₂ (oxidised) — Redox also occurs.

(c)
Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

Displacement + Redox.
Cu more reactive than Ag → Cu displaces Ag from solution (Displacement). Cu: 0 → +2 (oxidised); Ag: +1 → 0 (reduced) — Redox simultaneously.

(d)
NaOH + HCl → NaCl + H₂O

Double Displacement + Neutralisation.
Na⁺ (from NaOH) and H⁺ (from HCl) exchange their anions OH⁻ and Cl⁻ (Double Displacement). Acid + Base → Salt + Water defines it as Neutralisation. No change in oxidation states → NOT a redox reaction.

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Tips, Tricks & Common Mistakes

Exam-focused strategies and the most frequently made errors — know what to avoid and what to remember.

✅ Tips & Tricks

🎯

OIL RIG — Never Forget Redox

Oxidation Is Loss of electrons; Reduction Is Gain of electrons. Write this acronym at the top of your answer page during exams. Also: the reducing agent is oxidised; the oxidising agent is reduced.

⚖️

Balance Elements Last — O and H First

When balancing complex equations, balance all elements except O and H first. Then balance H. Balance O last using water molecules. This systematic approach avoids loops.

🧲

Activity Series — LEO the LION says GER

More reactive metals are higher in the activity series. For displacement: the metal doing the displacing must be ABOVE the displaced metal. K>Na>Ca>Mg>Al>Zn>Fe>Pb>H>Cu>Ag>Au

💡

Decomposition Energy Sources — "THE PHOTO"

Thermal = Heat | Electrolytic = Electricity | Photolytic = Light (photons). Remember: Silver salts (AgCl, AgBr) are always photolytic.

🔬

State Symbols in Board Exams — Always Include!

Include (s), (l), (g), (aq) — you often get a dedicated half-mark for state symbols. Also include ↓ for precipitate and ↑ for gas. Δ over the arrow shows heat was applied.

🎨

Colour Changes to Memorise

CuSO₄: blue → FeSO₄: green (Fe displaces Cu). CuO black → Cu reddish-brown (reduction). Ag white → turns grey (photo). FeSO₄·7H₂O green → Fe₂O₃ reddish-brown (heating).

📐

LCM Method for Tricky Balancing

When O appears in different compounds on both sides, use LCM of the subscripts. Example: O₂ (pairs of 2) vs Al₂O₃ (groups of 3) → LCM = 6, so you need 3O₂ and 2Al₂O₃.

❌ Common Mistakes

🚫

Changing Subscripts to Balance

NEVER change subscripts (e.g., H₂O → H₃O) to balance an equation. Subscripts define the compound — changing them creates a different substance. Only adjust COEFFICIENTS (the large numbers in front).

🚫

Confusing Oxidising and Reducing Agents

Students often say "the substance that gets oxidised is the oxidising agent" — this is WRONG. The reducing agent gets oxidised. The oxidising agent gets reduced. It's the OPPOSITE of what the name suggests.

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Stating H₂ is at Anode in Electrolysis

H₂ is collected at the CATHODE (−ve electrode), not anode. At cathode: H⁺ + e⁻ → H (reduction). O₂ is at anode. Remember: Cathode = Cations gather (H⁺ → H₂).

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Saying All Exothermic Reactions are Combustion

Combustion is always exothermic, but not all exothermic reactions are combustion. CaO + H₂O → Ca(OH)₂ is exothermic AND a combination reaction, not combustion. Classify carefully.

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Forgetting Arrow Direction in Displacement

For displacement to occur, the displacing element MUST be higher in the activity series. Cu cannot displace Zn from ZnSO₄. Always check relative reactivity before writing the equation.

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Writing Fe₂O₃ as the Formula for Rust

Rust is hydrated iron(III) oxide: Fe₂O₃·xH₂O, not simply Fe₂O₃. The 'x' indicates a variable number of water molecules. Writing just Fe₂O₃ is only partially correct for rusting.

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Omitting the Precipitate Arrow (↓)

In double displacement reactions where an insoluble product forms, the ↓ symbol is mandatory in the equation. Similarly, ↑ for gases. Omitting these reduces marks in board exams.

🧠 Memory Aids & Mnemonics

Redox

OIL RIG — Oxidation Is Loss; Reduction Is Gain (of electrons)

Activity Series (Top)

"Potassium Needs Constant Maintenance, Always Zap Fried Pears Hastily"
K, Na, Ca, Mg, Al, Zn, Fe, Pb, H

Decomposition Types

TEPThermal · Electrolytic · Photolytic

Endothermic vs Exothermic

ENdo = ENters (energy enters/absorbed)
EXo = EXits (energy exits/released)

Combination Pattern

A + B → AB
Many go in, One comes out

Photolytic Agents

Silver salts ALWAYS use light: AgCl, AgBr, AgI → photolytic decomposition

Rusting Needs BOTH

Rust needs O₂ AND H₂O — no rust in dry air; no rust in boiled water sealed with oil

Thermite

Thermite = Track welding
Fe₂O₃ + 2Al → Al₂O₃ + 2Fe(l) at ~2500°C

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ACADEMIA AETERNUM तमसो मा ज्योतिर्गमय · Est. 2025
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Class 10 Chemical Reactions Notes Made Easy – Chapter 1 Explained
Class 10 Chemical Reactions Notes Made Easy – Chapter 1 Explained — Complete Notes & Solutions · academia-aeternum.com
Chemical reactions are everywhere around us—rusting of iron, burning of fuels, digestion of food, photosynthesis in plants, and many more. A chemical reaction can be identified by observable changes such as change in colour, evolution of a gas, change in temperature, or formation of a precipitate. To represent these reactions clearly, we use chemical equations, where reactants (substances taking part in the reaction) are written on the left side and products (new substances formed) are written…
🎓 Class 10 📐 Science 📖 NCERT ✅ Free Access 🏆 CBSE · JEE
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