Class IX · Chapter 11 · NCERT Mathematics

CHAPTER 11

Surface Areas and Volumes

3D Mensuration for All Solids

Unwrap a cylinder, slice a sphere, pour a cone — three-dimensional shapes yield their secrets to algebra.

\(V(Sphere) = 4/3·πr³\)
13 CBSE Marks
Difficulty
8 Topics
Very High Board Weight

Topics Covered

8 key topics in this chapter

Surface Area of Cuboid & Cube
Surface Area of Right Circular Cylinder
Surface Area of Right Circular Cone
Surface Area of Sphere & Hemisphere
Volume of Cuboid & Cube
Volume of Cylinder
Volume of Cone
Volume of Sphere & Hemisphere

Study Resources

Key Formulas & Identities

Formula / Rule Expression
Cuboid TSA \(2(lb + bh + hl)\)
Cube TSA \(6a²\)
Cylinder CSA \(2πrh\)
Cylinder TSA \(2πr(r+h)\)
Cone CSA \(πrl (l = slant height = √(r²+h²))\)
Cone TSA \(πr(r+l)\)
Sphere SA \(4πr²\)
Hemisphere TSA \(3πr²\)
Cuboid Volume \(l × b × h\)
Cube Volume \(a³\)
Cylinder Volume \(πr²h\)
Cone Volume \(⅓πr²h\)
Sphere Volume \(⁴⁄₃πr³\)
Hemisphere Volume \(⅔πr³\)

Important Points to Remember

Lateral (Curved) Surface Area excludes the base(s). Total Surface Area includes all faces. Always read the problem carefully.
Slant height of a cone: l = √(r² + h²). This follows from Pythagoras — the slant is the hypotenuse.
A hemisphere has curved SA = 2πr² and flat circular face area = πr², so TSA = 3πr².
Volume formulae to memorise: Cube = a³; Cuboid = lbh; Cylinder = πr²h; Cone = ⅓πr²h; Sphere = ⁴⁄₃πr³; Hemisphere = ⅔πr³.
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