Heredity — NCERT Solutions | Class 10 Science | Academia Aeternum
Ch 8  ·  Q–
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Class 10 Science Exercise NCERT Solutions Olympiad Board Exam
Chapter 8

Heredity

Step-by-step NCERT solutions with stress–strain analysis and exam-oriented hints for Boards, JEE & NEET.

4 Questions
15-20 min Ideal time
Q1 Now at
Q1
NUMERIC3 marks
A Mendelian experiment consisted of breeding tall pea plants bearing violet flowers with short pea plants bearing white flowers. The progeny all bore violet flowers, but almost half of them were short. This suggests that the genetic make-up of the tall parent can be depicted as
(a) TTWW
(b) TTww
(c) TtWW
(d) TtWw

Theory Required to Solve

  • Trait and Allele: Each character (height, flower colour) is controlled by a pair of alleles.
  • Dominance: Dominant allele expresses itself in heterozygous condition (T = tall, W = violet).
  • Recessive Trait: Expressed only when both alleles are recessive (tt = short, ww = white).
  • Law of Segregation: Alleles separate during gamete formation and recombine during fertilization.
  • Dihybrid Cross Logic: When two traits are involved, each trait is inherited independently.

Solution Roadmap

  1. Identify dominant and recessive traits from given observations.
  2. Use offspring phenotype to deduce genotype of parents.
  3. Analyze height trait separately.
  4. Analyze flower colour trait separately.
  5. Combine both to get final genotype.

Step-by-Step Solution

Step 1: Identify dominance

All progeny have violet flowers ⇒ Violet colour is dominant (W) over white (w).

Step 2: Analyze flower colour inheritance

Since one parent is white (ww), and all offspring are violet, the other parent must supply dominant allele W in every case.

This is possible only if tall parent has genotype: \[ Ww \text{ or } WW \]

Step 3: Analyze height inheritance

Short parent genotype = tt
Almost half offspring are short ⇒ ratio ≈ 1:1

This occurs only when: \[ Tt \times tt \]

Gametes from tall parent: \[ T, t \]

Offspring: \[ Tt \; (\text{tall}), \quad tt \; (\text{short}) \]

Step 4: Combine both traits

Height genotype of tall parent = Tt
Flower colour must include dominant W but may carry w ⇒ Ww

Therefore, genotype of tall parent: \[ TtWw \]

Step 5: Match with options

Correct answer is:
(d) TtWw

Significance for Exams

  • CBSE Board Exams: Frequently asked to test understanding of dominance and genotype deduction.
  • Assertion-Reason & MCQs: Helps in predicting genotype from phenotype ratios.
  • Competitive Exams (NEET, Olympiads): Builds foundation for dihybrid cross and probability-based genetics.
  • Conceptual Clarity: Strengthens linkage between phenotype ratios and genetic constitution.
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1 / 4  ·  25%
Q2 →
Q2
NUMERIC3 marks
A study found that children with light-coloured eyes are likely to have parents with light-coloured eyes. On this basis, can we say anything about whether the light eye colour trait is dominant or recessive? Why or why not?

Theory Required to Solve

  • Dominant Trait: A dominant allele expresses itself even in heterozygous condition.
  • Recessive Trait: A recessive allele expresses only when present in homozygous condition.
  • Genotype vs Phenotype: Same phenotype may arise from different genotypes (e.g., AA or Aa).
  • Inheritance Pattern: To determine dominance, we need controlled crosses or pedigree analysis.
  • Key Principle: Observation of similar traits in parents and offspring alone is insufficient to determine dominance.

Solution Roadmap

  1. Understand what is given: children and parents both have light eye colour.
  2. Check if this observation distinguishes dominant vs recessive inheritance.
  3. Test both possibilities logically.
  4. Conclude whether available data is sufficient.

Step-by-Step Solution

Step 1: Given Observation

Children with light-coloured eyes have parents with light-coloured eyes.

Step 2: Case 1 — Assume light eye colour is dominant

Let dominant allele = L (light), recessive = l (dark)

Possible genotypes of parents: \[ LL \text{ or } Ll \]

Such parents can produce: \[ LL, Ll, \text{ or } ll \]

Hence, even dominant parents can have children with different traits. But they can also have light-eyed children.

Step 3: Case 2 — Assume light eye colour is recessive

Let recessive allele = l (light), dominant = L (dark)

Parents must be: \[ ll \]

Cross: \[ ll \times ll \Rightarrow ll \]

All children will have light eyes.

Step 4: Compare both cases

  • Dominant case → light-eyed children possible
  • Recessive case → light-eyed children also possible

Thus, both genetic models explain the observation.

Step 5: Final Conclusion

We cannot determine whether light eye colour is dominant or recessive based only on this information. Additional data such as:

  • Cross-breeding results
  • Pedigree analysis over generations
  • Cases where parents and offspring differ

would be required.

Significance for Exams

  • CBSE Board Exams: Tests reasoning ability—students must avoid jumping to conclusions from incomplete data.
  • Assertion-Reason Questions: Commonly checks understanding that correlation does not imply dominance.
  • Competitive Exams (NEET, Olympiads): Builds foundation for pedigree analysis and inheritance patterns.
  • Conceptual Strength: Reinforces that proper genetic conclusions require controlled crosses, not just observations.
← Q1
2 / 4  ·  50%
Q3 →
Q3
NUMERIC3 marks
Outline a project which aims to find the dominant coat colour in dogs.

Theory Required to Design the Project

  • Dominant Trait: Expressed in both homozygous and heterozygous conditions.
  • Recessive Trait: Expressed only in homozygous condition.
  • Monohybrid Cross: Study of inheritance of a single trait.
  • Law of Dominance: In a pair of alleles, one may mask the expression of the other.
  • Phenotypic Ratio: Dominant traits typically appear more frequently (e.g., 3:1 in F2 generation).
  • Test Cross: Crossing with a recessive individual helps reveal hidden alleles.

Project Design Roadmap

  1. Define objective clearly.
  2. Select suitable population with variation.
  3. Perform controlled crosses.
  4. Record observations generation-wise.
  5. Analyze ratios and patterns.
  6. Validate using second-generation crosses.
  7. Draw genetically justified conclusion.

Step-by-Step Project Outline

Step 1: Objective

To determine which coat colour in dogs is dominant using inheritance patterns.

Step 2: Selection of Dog Population

Select dogs with clearly distinguishable coat colours such as black, brown, white, etc. Ensure parentage records are available.

Step 3: Collection of Data

Record coat colour of:

  • Parent dogs (P generation)
  • Offspring (F1 generation)
  • If available, previous generations

Step 4: Perform Controlled Crosses

Example cross:

Black dog × Brown dog

Repeat with multiple pairs to ensure reliability.

Step 5: Record F1 Generation

Observe coat colour of all offspring.

  • If all offspring show same colour → that trait is likely dominant.

Step 6: Perform F1 × F1 Cross (Second Generation)

Cross two F1 individuals:

\[ F1 \times F1 \]

Step 7: Analyze F2 Generation

Count number of each coat colour.

If ratio is approximately: \[ 3:1 \] then dominant and recessive traits are confirmed.

Step 8: Test Cross (Optional but Strong Evidence)

Cross F1 individual with recessive parent:

\[ F1 \times rr \]

  • 1:1 ratio confirms heterozygous dominant individual.

Step 9: Identify Dominant Trait

The coat colour that:

  • Appears in all F1 offspring
  • Appears in majority in F2 (3:1 ratio)

is the dominant coat colour.

Step 10: Conclusion and Report

Compile observations, ratios, and genetic interpretation to conclude dominance.

Significance for Exams

  • CBSE Board Exams: Frequently asked as application-based question to test understanding of Mendelian genetics.
  • Case-Based Questions: Helps in designing experiments and interpreting inheritance patterns.
  • Competitive Exams (NEET, Olympiads): Builds strong foundation in experimental genetics and ratio analysis.
  • Practical Understanding: Connects theoretical genetics with real-life biological observations.
← Q2
3 / 4  ·  75%
Q4 →
Q4
NUMERIC3 marks
How is the equal genetic contribution of male and female parents ensured in the progeny?

Theory Required to Solve

  • Chromosomes: Structures carrying genetic information (genes).
  • Diploid (2n): Cells containing two sets of chromosomes (one from each parent).
  • Haploid (n): Gametes contain only one set of chromosomes.
  • Meiosis: Reduction division that produces haploid gametes.
  • Fertilization: Fusion of male and female gametes to restore diploid condition.
  • Law of Segregation: Alleles separate during gamete formation ensuring equal distribution.

Solution Roadmap

  1. Understand chromosome number in parents.
  2. Explain formation of gametes through meiosis.
  3. Show how each gamete carries half genetic material.
  4. Explain fertilization restoring full chromosome number.
  5. Conclude equal contribution from both parents.

Step-by-Step Solution

Step 1: Chromosome Number in Parents

In humans (and most organisms), body cells are diploid: \[ 2n \] This means chromosomes exist in pairs—one from mother and one from father.

Step 2: Formation of Gametes (Meiosis)

During gamete formation:

  • Male produces sperm
  • Female produces eggs (ova)

Meiosis reduces chromosome number: \[ 2n \rightarrow n \]

Thus, each gamete carries only half the genetic material.

Step 3: Equal Contribution at Gamete Level

Each parent contributes: \[ n \text{ chromosomes} \]

Step 4: Fertilization

Fusion of gametes: \[ n + n \rightarrow 2n \]

This forms a zygote with complete chromosome set.

Step 5: Genetic Contribution

Since:

  • Half chromosomes come from sperm (father)
  • Half chromosomes come from egg (mother)

Therefore, genetic contribution is: \[ 50\% \text{ from father} + 50\% \text{ from mother} \]

Final Conclusion

Equal genetic contribution is ensured by:

  • Formation of haploid gametes through meiosis
  • Fusion of gametes during fertilization

This guarantees that offspring inherit equal genetic material from both parents.

Significance for Exams

  • CBSE Board Exams: Frequently asked conceptual question on meiosis and fertilization.
  • Assertion-Reason Questions: Tests understanding of chromosome number reduction and restoration.
  • Competitive Exams (NEET, Olympiads): Forms the basis of genetics, inheritance, and variation.
  • Conceptual Clarity: Essential for understanding how traits are passed equally across generations.
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Class 10 Heredity NCERT Solutions (Chapter 8 Exercises Explained)
Class 10 Heredity NCERT Solutions (Chapter 8 Exercises Explained) — Complete Notes & Solutions · academia-aeternum.com
Unlock clear, stepwise, and original solutions for each exercise in NCERT Class 10 Science Chapter 8 "Heredity." This guide is designed to help students confidently resolve textbook questions, master key genetics concepts, and excel in board examinations. Every answer is explained in student-friendly language, supporting quick revision and solid understanding of inheritance, Mendelian laws, traits, and gene action for top exam performance.
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