Class XI · Chapter 7 · NCERT Mathematics

CHAPTER 07

Binomial Theorem

Pascal's Pyramid & Expanding Powers

From Pascal's triangle to general term — conquer expansion at any power.

\(T_{r+1} = ⁿCᵣ · aⁿ⁻ʳ · bʳ\)
8 CBSE Marks
Difficulty
8 Topics
High JEE Weight

Topics Covered

8 key topics in this chapter

Binomial Theorem for Positive Integers
Pascal's Triangle
General Term T_{r+1}
Middle Term
Independent Term
Properties of Binomial Coefficients
Greatest Coefficient & Greatest Term
Multinomial Expansion (intro)

Study Resources

𝑓 Key Formulae

Essential mathematical expressions for this chapter — understand derivations, not just results.

Binomial Expansion
\[(a+b)^n = \sum_{r=0}^{n} {}^nC_r\, a^{n-r}\, b^r\]
📌 n is a non-negative integer
General Term
\[T_{r+1} = {}^nC_r\, a^{n-r}\, b^r\]
📌 r starts from 0
Middle Term (odd n)
\[\text{If }n\text{ even: }T_{n/2+1}\text{ (one middle term)}\]
📌 If n odd: two middle terms T_{(n+1)/2} and T_{(n+3)/2}
Coeff. Sum
\[\sum_{r=0}^n {}^nC_r = 2^n\]
📌 Put a=b=1
Alternating Sum
\[\sum_{r=0}^n (-1)^r\,{}^nC_r = 0\]
📌 Put a=1, b=−1
Even/Odd Coeff
\[{}^nC_0+{}^nC_2+\cdots = {}^nC_1+{}^nC_3+\cdots = 2^{n-1}\]
📌 Sum of even = sum of odd binomial coefficients

🎯 Exam-Ready Insights

Important points to remember — curated from CBSE Board question patterns.

01

CBSE 5-mark: "Find the middle term in (x + 1/x)⁸" — identify n, apply Tᵣ₊₁ formula, then simplify.

02

Finding the independent term (constant term): set the power of x in Tᵣ₊₁ to zero and solve for r.

03

Greatest binomial coefficient is ⁿCₙ/₂ (for even n) — appears in MCQs.

04

Pascal's triangle row for n gives all ⁿCᵣ values directly — useful for quick checking.

05

Sum of all binomial coefficients = 2ⁿ (put x=1 in (1+x)ⁿ).

🏆 Competitive Exam Strategy

Targeted tips for JEE Main, JEE Advanced, NEET, BITSAT, and KVPY.

JEE Main

JEE Main frequently asks for the coefficient of xᵏ or the rational term in irrational expansions like (∛2 + ∜3)ⁿ — use Tᵣ₊₁ and integer-exponent conditions.

JEE Advanced

JEE Advanced tests numerical value of sums like Σr·ⁿCᵣ = n·2ⁿ⁻¹ — derive these by differentiating (1+x)ⁿ.

BITSAT

BITSAT gives "find the number of terms in the expansion" — for (a+b+c)ⁿ it is (n+1)(n+2)/2, not n+1.

KVPY

KVPY expects you to use binomial theorem to prove divisibility results (e.g. 7ⁿ − 1 is divisible by 6) — a classic elegant application.

⚠️ Common Mistakes to Avoid

Treating Tᵣ as the rth term — it is actually T₁ at r=0; the (r+1)th term is Tᵣ₊₁.

Using the wrong middle term formula when n is odd vs even.

Not simplifying ⁿCᵣ before multiplying — leads to arithmetic errors.

Forgetting that the expansion has n+1 terms (0 to n), not n terms.

💡 Key Takeaways

The binomial theorem expands (a+b)ⁿ into n+1 terms for any non-negative integer n.

General term Tᵣ₊₁ = ⁿCᵣ·aⁿ⁻ʳ·bʳ is the workhorse of this chapter — master it.

The sum of binomial coefficients equals 2ⁿ; alternating sum equals 0.

Middle term(s): one if n is even, two if n is odd.

The chapter connects to probability (through combinations) and calculus (through infinite series in higher classes).

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